Solve for x
x\leq \frac{50}{3}
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80x+2500-50x\leq 3000
Use the distributive property to multiply 50-x by 50.
30x+2500\leq 3000
Combine 80x and -50x to get 30x.
30x\leq 3000-2500
Subtract 2500 from both sides.
30x\leq 500
Subtract 2500 from 3000 to get 500.
x\leq \frac{500}{30}
Divide both sides by 30. Since 30 is positive, the inequality direction remains the same.
x\leq \frac{50}{3}
Reduce the fraction \frac{500}{30} to lowest terms by extracting and canceling out 10.
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