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\left(3x+2y\right)\left(9x^{2}-6xy+4y^{2}\right)
Rewrite 8y^{3}+27x^{3} as \left(3x\right)^{3}+\left(2y\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).