Solve 8x-a12=28-8x

$$8 x - a 12 = 28 - 8 x$$

Solve for a_12

$$a_{12}=16x-28$$

Steps for Solving Linear Equation

Subtract 8x from both sides.

$$-a_{12}=28-8x-8x$$

Combine -8x and -8x to get -16x.

$$-a_{12}=28-16x$$

Divide both sides by -1.

$$\frac{-a_{12}}{-1}=\frac{28-16x}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$a_{12}=\frac{28-16x}{-1}$$

Divide 28-16x by -1.

$$a_{12}=16x-28$$

Solve for x

$$x=\frac{a_{12}+28}{16}$$

Steps for Solving Linear Equation

Add 8x to both sides.

$$8x-a_{12}+8x=28$$

Combine 8x and 8x to get 16x.

$$16x-a_{12}=28$$

Add a_{12} to both sides.

$$16x=28+a_{12}$$

The equation is in standard form.

$$16x=a_{12}+28$$

Divide both sides by 16.

$$\frac{16x}{16}=\frac{a_{12}+28}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$x=\frac{a_{12}+28}{16}$$

Divide 28+a_{12} by 16.

$$x=\frac{a_{12}}{16}+\frac{7}{4}$$