Solve 8x-4x^2-5

$$8 x - 4 x ^ { 2 } - 5$$

Differentiate w.r.t. x

$$8-8x$$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$8x^{1-1}+2\left(-4\right)x^{2-1}$$

Subtract 1 from 1.

$$8x^{0}+2\left(-4\right)x^{2-1}$$

Multiply 2 times -4.

$$8x^{0}-8x^{2-1}$$

Subtract 1 from 2.

$$8x^{0}-8x^{1}$$

For any term t, t^{1}=t.

$$8x^{0}-8x$$

For any term t except 0, t^{0}=1.

$$8\times 1-8x$$

For any term t, t\times 1=t and 1t=t.

$$8-8x$$

Evaluate

$$-4x^{2}+8x-5$$