Solve for x
x=\frac{3\left(y+4\right)}{8}
Solve for y
y=\frac{8x}{3}-4
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8x=12+3y
Add 3y to both sides.
8x=3y+12
The equation is in standard form.
\frac{8x}{8}=\frac{3y+12}{8}
Divide both sides by 8.
x=\frac{3y+12}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{3y}{8}+\frac{3}{2}
Divide 12+3y by 8.
-3y=12-8x
Subtract 8x from both sides.
\frac{-3y}{-3}=\frac{12-8x}{-3}
Divide both sides by -3.
y=\frac{12-8x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{8x}{3}-4
Divide 12-8x by -3.
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