Solve 8x(x+2)-2=2(8x-1)

$$8 x ( x + 2 ) - 2 = 2 ( 8 x - 1 )$$

Solve for x

$$x=0$$

Steps by Finding Square Root

Use the distributive property to multiply 8x by x+2.

$$8x^{2}+16x-2=2\left(8x-1\right)$$

Use the distributive property to multiply 2 by 8x-1.

$$8x^{2}+16x-2=16x-2$$

Subtract 16x from both sides.

$$8x^{2}+16x-2-16x=-2$$

Combine 16x and -16x to get 0.

$$8x^{2}-2=-2$$

Add 2 to both sides.

$$8x^{2}=-2+2$$

Add -2 and 2 to get 0.

$$8x^{2}=0$$

Divide both sides by 8. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

Take the square root of both sides of the equation.

$$x=0 x=0$$

The equation is now solved. Solutions are the same.

$$x=0$$

Steps Using the Quadratic Formula

Use the distributive property to multiply 8x by x+2.

$$8x^{2}+16x-2=2\left(8x-1\right)$$

Use the distributive property to multiply 2 by 8x-1.

$$8x^{2}+16x-2=16x-2$$

Subtract 16x from both sides.

$$8x^{2}+16x-2-16x=-2$$

Combine 16x and -16x to get 0.

$$8x^{2}-2=-2$$

Add 2 to both sides.

$$8x^{2}-2+2=0$$

Add -2 and 2 to get 0.

$$8x^{2}=0$$

Divide both sides by 8. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$x=\frac{0±0}{2}$$

Divide 0 by 2.

$$x=0$$