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x\left(8x^{3}-y^{3}\right)
Factor out x.
\left(2x-y\right)\left(4x^{2}+2xy+y^{2}\right)
Consider 8x^{3}-y^{3}. Rewrite 8x^{3}-y^{3} as \left(2x\right)^{3}-y^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
x\left(2x-y\right)\left(4x^{2}+2xy+y^{2}\right)
Rewrite the complete factored expression.