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\left(2x-3\right)\left(4x^{2}+6x+9\right)
Rewrite 8x^{3}-27 as \left(2x\right)^{3}-3^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial 4x^{2}+6x+9 is not factored since it does not have any rational roots.