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\left(2x+y^{3}\right)\left(4x^{2}-2xy^{3}+y^{6}\right)
Rewrite 8x^{3}+y^{9} as \left(2x\right)^{3}+\left(y^{3}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).