Solve for x
x=\frac{-3y-5}{8}
Solve for y
y=\frac{-8x-5}{3}
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8x=-5-3y
Subtract 3y from both sides.
8x=-3y-5
The equation is in standard form.
\frac{8x}{8}=\frac{-3y-5}{8}
Divide both sides by 8.
x=\frac{-3y-5}{8}
Dividing by 8 undoes the multiplication by 8.
3y=-5-8x
Subtract 8x from both sides.
3y=-8x-5
The equation is in standard form.
\frac{3y}{3}=\frac{-8x-5}{3}
Divide both sides by 3.
y=\frac{-8x-5}{3}
Dividing by 3 undoes the multiplication by 3.
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