Solve for n
n=-\frac{-3\cos(\theta )+1}{8\theta }
\theta \neq 0
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8n\theta =-1+3\cos(\theta )
Add 3\cos(\theta ) to both sides.
8\theta n=3\cos(\theta )-1
The equation is in standard form.
\frac{8\theta n}{8\theta }=\frac{3\cos(\theta )-1}{8\theta }
Divide both sides by 8\theta .
n=\frac{3\cos(\theta )-1}{8\theta }
Dividing by 8\theta undoes the multiplication by 8\theta .
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