Solve 8k+4-11k+9

$$8 k + 4 - 11 k + 9$$

Evaluate

$$13-3k$$

Solution Steps

Combine 8k and -11k to get -3k.

$$-3k+4+9$$

Add 4 and 9 to get 13.

$$-3k+13$$

Differentiate w.r.t. k

$$-3$$

Steps Using Derivative Rule for Sum

Combine 8k and -11k to get -3k.

$$\frac{\mathrm{d}}{\mathrm{d}k}(-3k+4+9)$$

Add 4 and 9 to get 13.

$$\frac{\mathrm{d}}{\mathrm{d}k}(-3k+13)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-3k^{1-1}$$

Subtract 1 from 1.

$$-3k^{0}$$

For any term t except 0, t^{0}=1.

$$-3$$