Solve for b
b=\frac{5t}{8}+\frac{3}{2}
Solve for t
t=\frac{8b-12}{5}
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8b=14+5t-2
Subtract 2 from both sides.
8b=12+5t
Subtract 2 from 14 to get 12.
8b=5t+12
The equation is in standard form.
\frac{8b}{8}=\frac{5t+12}{8}
Divide both sides by 8.
b=\frac{5t+12}{8}
Dividing by 8 undoes the multiplication by 8.
b=\frac{5t}{8}+\frac{3}{2}
Divide 12+5t by 8.
14+5t=8b+2
Swap sides so that all variable terms are on the left hand side.
5t=8b+2-14
Subtract 14 from both sides.
5t=8b-12
Subtract 14 from 2 to get -12.
\frac{5t}{5}=\frac{8b-12}{5}
Divide both sides by 5.
t=\frac{8b-12}{5}
Dividing by 5 undoes the multiplication by 5.
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