Solve for a
a=\frac{x^{4}-4x^{3}+6x^{2}-8x+1}{8}
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8a=x^{4}-4x^{3}+6x^{2}-8x+1
The equation is in standard form.
\frac{8a}{8}=\frac{x^{4}-4x^{3}+6x^{2}-8x+1}{8}
Divide both sides by 8.
a=\frac{x^{4}-4x^{3}+6x^{2}-8x+1}{8}
Dividing by 8 undoes the multiplication by 8.
a=\frac{x^{4}}{8}-\frac{x^{3}}{2}+\frac{3x^{2}}{4}-x+\frac{1}{8}
Divide x^{4}-4x^{3}+6x^{2}-8x+1 by 8.
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