Solve 8-9(x+1)=ax+4

$$8 - 9 ( x + 1 ) = a x + 4$$

Solve for a

$$a=-9-\frac{5}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply -9 by x+1.

$$8-9x-9=ax+4$$

Subtract 9 from 8 to get -1.

$$-1-9x=ax+4$$

Swap sides so that all variable terms are on the left hand side.

$$ax+4=-1-9x$$

Subtract 4 from both sides.

$$ax=-1-9x-4$$

Subtract 4 from -1 to get -5.

$$ax=-5-9x$$

The equation is in standard form.

$$xa=-9x-5$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{-9x-5}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{-9x-5}{x}$$

Divide -5-9x by x.

$$a=-9-\frac{5}{x}$$

Solve for x

$$x=-\frac{5}{a+9}$$

$$a\neq -9$$

Steps for Solving Linear Equation

Use the distributive property to multiply -9 by x+1.

$$8-9x-9=ax+4$$

Subtract 9 from 8 to get -1.

$$-1-9x=ax+4$$

Subtract ax from both sides.

$$-1-9x-ax=4$$

Add 1 to both sides.

$$-9x-ax=4+1$$

Add 4 and 1 to get 5.

$$-9x-ax=5$$

Combine all terms containing x.

$$\left(-9-a\right)x=5$$

The equation is in standard form.

$$\left(-a-9\right)x=5$$

Divide both sides by -9-a.

$$\frac{\left(-a-9\right)x}{-a-9}=\frac{5}{-a-9}$$

Dividing by -9-a undoes the multiplication by -9-a.

$$x=\frac{5}{-a-9}$$

Divide 5 by -9-a.

$$x=-\frac{5}{a+9}$$