Solve 8-3[11x-2(5x-3)+4]=x+2

$$8 - 3 [ 11 x - 2 ( 5 x - 3 ) + 4 ] = x + 2$$

Solve for x

$$x=-6$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by 5x-3.

$$8-3\left(11x-10x+6+4\right)=x+2$$

Combine 11x and -10x to get x.

$$8-3\left(x+6+4\right)=x+2$$

Add 6 and 4 to get 10.

$$8-3\left(x+10\right)=x+2$$

Use the distributive property to multiply -3 by x+10.

$$8-3x-30=x+2$$

Subtract 30 from 8 to get -22.

$$-22-3x=x+2$$

Subtract x from both sides.

$$-22-3x-x=2$$

Combine -3x and -x to get -4x.

$$-22-4x=2$$

Add 22 to both sides.

$$-4x=2+22$$

Add 2 and 22 to get 24.

$$-4x=24$$

Divide both sides by -4.

$$x=\frac{24}{-4}$$

Divide 24 by -4 to get -6.

$$x=-6$$