Solve 8-2y=4+16/3-2/3y

$$8 - 2 y = 4 + \frac { 16 } { 3 } - \frac { 2 } { 3 } y$$

Solve for y

$$y=-1$$

Steps for Solving Linear Equation

Convert 4 to fraction \frac{12}{3}.

$$8-2y=\frac{12}{3}+\frac{16}{3}-\frac{2}{3}y$$

Since \frac{12}{3} and \frac{16}{3} have the same denominator, add them by adding their numerators.

$$8-2y=\frac{12+16}{3}-\frac{2}{3}y$$

Add 12 and 16 to get 28.

$$8-2y=\frac{28}{3}-\frac{2}{3}y$$

Add \frac{2}{3}y to both sides.

$$8-2y+\frac{2}{3}y=\frac{28}{3}$$

Combine -2y and \frac{2}{3}y to get -\frac{4}{3}y.

$$8-\frac{4}{3}y=\frac{28}{3}$$

Subtract 8 from both sides.

$$-\frac{4}{3}y=\frac{28}{3}-8$$

Convert 8 to fraction \frac{24}{3}.

$$-\frac{4}{3}y=\frac{28}{3}-\frac{24}{3}$$

Since \frac{28}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{4}{3}y=\frac{28-24}{3}$$

Subtract 24 from 28 to get 4.

$$-\frac{4}{3}y=\frac{4}{3}$$

Multiply both sides by -\frac{3}{4}, the reciprocal of -\frac{4}{3}.

$$y=\frac{4}{3}\left(-\frac{3}{4}\right)$$

Multiply \frac{4}{3} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{4\left(-3\right)}{3\times 4}$$

Cancel out 4 in both numerator and denominator.

$$y=\frac{-3}{3}$$

Divide -3 by 3 to get -1.

$$y=-1$$