Solve 8-1/2*(-4/3)+4^2*(-1)^3

$$8 - \frac { 1 } { 2 } \times ( - \frac { 4 } { 3 } ) + 4 ^ { 2 } \times ( - 1 ) ^ { 3 }$$

Evaluate

$$-\frac{22}{3}\approx -7.333333333$$

Solution Steps

Multiply \frac{1}{2} times -\frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$8-\frac{1\left(-4\right)}{2\times 3}+4^{2}\left(-1\right)^{3}$$

Do the multiplications in the fraction \frac{1\left(-4\right)}{2\times 3}.

$$8-\frac{-4}{6}+4^{2}\left(-1\right)^{3}$$

Reduce the fraction \frac{-4}{6} to lowest terms by extracting and canceling out 2.

$$8-\left(-\frac{2}{3}\right)+4^{2}\left(-1\right)^{3}$$

The opposite of -\frac{2}{3} is \frac{2}{3}.

$$8+\frac{2}{3}+4^{2}\left(-1\right)^{3}$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{24}{3}+\frac{2}{3}+4^{2}\left(-1\right)^{3}$$

Since \frac{24}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{24+2}{3}+4^{2}\left(-1\right)^{3}$$

Add 24 and 2 to get 26.

$$\frac{26}{3}+4^{2}\left(-1\right)^{3}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{26}{3}+16\left(-1\right)^{3}$$

Calculate -1 to the power of 3 and get -1.

$$\frac{26}{3}+16\left(-1\right)$$

Multiply 16 and -1 to get -16.

$$\frac{26}{3}-16$$

Convert 16 to fraction \frac{48}{3}.

$$\frac{26}{3}-\frac{48}{3}$$

Since \frac{26}{3} and \frac{48}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{26-48}{3}$$

Subtract 48 from 26 to get -22.

$$-\frac{22}{3}$$

Factor

$$-\frac{22}{3} = -7\frac{1}{3} = -7.333333333333333$$