Solve 8(2y+3)+3(y-5)=0

$$8 ( 2 y + 3 ) + 3 ( y - 5 ) = 0$$

Solve for y

$$y=-\frac{9}{19}\approx -0.473684211$$

Steps for Solving Linear Equation

Use the distributive property to multiply 8 by 2y+3.

$$16y+24+3\left(y-5\right)=0$$

Use the distributive property to multiply 3 by y-5.

$$16y+24+3y-15=0$$

Combine 16y and 3y to get 19y.

$$19y+24-15=0$$

Subtract 15 from 24 to get 9.

$$19y+9=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$19y=-9$$

Divide both sides by 19.

$$y=\frac{-9}{19}$$

Fraction \frac{-9}{19} can be rewritten as -\frac{9}{19} by extracting the negative sign.

$$y=-\frac{9}{19}$$