Solve 8(18/3)-4+3(18/3)=7(18/3)+18/3+14

$$8 ( \frac { 18 } { 3 } ) - 4 + 3 ( \frac { 18 } { 3 } ) = 7 ( \frac { 18 } { 3 } ) + \frac { 18 } { 3 } + 14$$

Verify

Solution Steps

Divide 18 by 3 to get 6.

$$8\times 6-4+3\times \frac{18}{3}=7\times \frac{18}{3}+\frac{18}{3}+14$$

Multiply 8 and 6 to get 48.

$$48-4+3\times \frac{18}{3}=7\times \frac{18}{3}+\frac{18}{3}+14$$

Subtract 4 from 48 to get 44.

$$44+3\times \frac{18}{3}=7\times \frac{18}{3}+\frac{18}{3}+14$$

Divide 18 by 3 to get 6.

$$44+3\times 6=7\times \frac{18}{3}+\frac{18}{3}+14$$

Multiply 3 and 6 to get 18.

$$44+18=7\times \frac{18}{3}+\frac{18}{3}+14$$

Add 44 and 18 to get 62.

$$62=7\times \frac{18}{3}+\frac{18}{3}+14$$

Divide 18 by 3 to get 6.

$$62=7\times 6+\frac{18}{3}+14$$

Multiply 7 and 6 to get 42.

$$62=42+\frac{18}{3}+14$$

Divide 18 by 3 to get 6.

$$62=42+6+14$$

Add 42 and 6 to get 48.

$$62=48+14$$

Add 48 and 14 to get 62.

$$62=62$$

Compare 62 and 62.

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