Solve 8(1^3/3)+9(2^2/3)-4(3/4)+2(5)

$$8 ( \frac { 1 ^ { 3 } } { 3 } ) + 9 ( \frac { 2 ^ { 2 } } { 3 } ) - 4 ( \frac { 3 } { 4 } ) + 2 ( 5 )$$

Evaluate

$$\frac{65}{3}\approx 21.666666667$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$8\times \frac{1}{3}+9\times \frac{2^{2}}{3}-4\times \frac{3}{4}+2\times 5$$

Multiply 8 and \frac{1}{3} to get \frac{8}{3}.

$$\frac{8}{3}+9\times \frac{2^{2}}{3}-4\times \frac{3}{4}+2\times 5$$

Calculate 2 to the power of 2 and get 4.

$$\frac{8}{3}+9\times \frac{4}{3}-4\times \frac{3}{4}+2\times 5$$

Express 9\times \frac{4}{3} as a single fraction.

$$\frac{8}{3}+\frac{9\times 4}{3}-4\times \frac{3}{4}+2\times 5$$

Multiply 9 and 4 to get 36.

$$\frac{8}{3}+\frac{36}{3}-4\times \frac{3}{4}+2\times 5$$

Since \frac{8}{3} and \frac{36}{3} have the same denominator, add them by adding their numerators.

$$\frac{8+36}{3}-4\times \frac{3}{4}+2\times 5$$

Add 8 and 36 to get 44.

$$\frac{44}{3}-4\times \frac{3}{4}+2\times 5$$

Cancel out 4 and 4.

$$\frac{44}{3}-3+2\times 5$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{44}{3}-\frac{9}{3}+2\times 5$$

Since \frac{44}{3} and \frac{9}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{44-9}{3}+2\times 5$$

Subtract 9 from 44 to get 35.

$$\frac{35}{3}+2\times 5$$

Multiply 2 and 5 to get 10.

$$\frac{35}{3}+10$$

Convert 10 to fraction \frac{30}{3}.

$$\frac{35}{3}+\frac{30}{3}$$

Since \frac{35}{3} and \frac{30}{3} have the same denominator, add them by adding their numerators.

$$\frac{35+30}{3}$$

Add 35 and 30 to get 65.

$$\frac{65}{3}$$

Factor

$$\frac{5 \cdot 13}{3} = 21\frac{2}{3} = 21.666666666666668$$