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8x^{4}+x^{2}-9=0
To factor the expression, solve the equation where it equals to 0.
±\frac{9}{8},±\frac{9}{4},±\frac{9}{2},±9,±\frac{3}{8},±\frac{3}{4},±\frac{3}{2},±3,±\frac{1}{8},±\frac{1}{4},±\frac{1}{2},±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -9 and q divides the leading coefficient 8. List all candidates \frac{p}{q}.
x=1
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
8x^{3}+8x^{2}+9x+9=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 8x^{4}+x^{2}-9 by x-1 to get 8x^{3}+8x^{2}+9x+9. To factor the result, solve the equation where it equals to 0.
±\frac{9}{8},±\frac{9}{4},±\frac{9}{2},±9,±\frac{3}{8},±\frac{3}{4},±\frac{3}{2},±3,±\frac{1}{8},±\frac{1}{4},±\frac{1}{2},±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 9 and q divides the leading coefficient 8. List all candidates \frac{p}{q}.
x=-1
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
8x^{2}+9=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 8x^{3}+8x^{2}+9x+9 by x+1 to get 8x^{2}+9. To factor the result, solve the equation where it equals to 0.
x=\frac{0±\sqrt{0^{2}-4\times 8\times 9}}{2\times 8}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 8 for a, 0 for b, and 9 for c in the quadratic formula.
x=\frac{0±\sqrt{-288}}{16}
Do the calculations.
8x^{2}+9
Polynomial 8x^{2}+9 is not factored since it does not have any rational roots.
\left(x-1\right)\left(x+1\right)\left(8x^{2}+9\right)
Rewrite the factored expression using the obtained roots.