Factor
\left(2a+5\right)\left(4a^{2}-10a+25\right)
Evaluate
8a^{3}+125
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\left(2a+5\right)\left(4a^{2}-10a+25\right)
Rewrite 8a^{3}+125 as \left(2a\right)^{3}+5^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right). Polynomial 4a^{2}-10a+25 is not factored since it does not have any rational roots.
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