Solve for x
x\leq \frac{37}{34}
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40x-3\left(2x-1\right)\leq 40
Multiply 8 and 5 to get 40.
40x-6x+3\leq 40
Use the distributive property to multiply -3 by 2x-1.
34x+3\leq 40
Combine 40x and -6x to get 34x.
34x\leq 40-3
Subtract 3 from both sides.
34x\leq 37
Subtract 3 from 40 to get 37.
x\leq \frac{37}{34}
Divide both sides by 34. Since 34 is positive, the inequality direction remains the same.
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