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\frac{\left(8\times 4+3\right)\times 2}{4\left(3\times 2+1\right)}
Divide \frac{8\times 4+3}{4} by \frac{3\times 2+1}{2} by multiplying \frac{8\times 4+3}{4} by the reciprocal of \frac{3\times 2+1}{2}.
\frac{3+4\times 8}{2\left(1+2\times 3\right)}
Cancel out 2 in both numerator and denominator.
\frac{3+32}{2\left(1+2\times 3\right)}
Multiply 4 and 8 to get 32.
\frac{35}{2\left(1+2\times 3\right)}
Add 3 and 32 to get 35.
\frac{35}{2\left(1+6\right)}
Multiply 2 and 3 to get 6.
\frac{35}{2\times 7}
Add 1 and 6 to get 7.
\frac{35}{14}
Multiply 2 and 7 to get 14.
\frac{5}{2}
Reduce the fraction \frac{35}{14} to lowest terms by extracting and canceling out 7.