Solve 81/5-11/2-27/10

$$8 \frac { 1 } { 5 } - 1 \frac { 1 } { 2 } - 2 \frac { 7 } { 10 }$$

Evaluate

$$4$$

Solution Steps

Multiply 8 and 5 to get 40.

$$\frac{40+1}{5}-\frac{1\times 2+1}{2}-\frac{2\times 10+7}{10}$$

Add 40 and 1 to get 41.

$$\frac{41}{5}-\frac{1\times 2+1}{2}-\frac{2\times 10+7}{10}$$

Multiply 1 and 2 to get 2.

$$\frac{41}{5}-\frac{2+1}{2}-\frac{2\times 10+7}{10}$$

Add 2 and 1 to get 3.

$$\frac{41}{5}-\frac{3}{2}-\frac{2\times 10+7}{10}$$

Least common multiple of 5 and 2 is 10. Convert \frac{41}{5} and \frac{3}{2} to fractions with denominator 10.

$$\frac{82}{10}-\frac{15}{10}-\frac{2\times 10+7}{10}$$

Since \frac{82}{10} and \frac{15}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{82-15}{10}-\frac{2\times 10+7}{10}$$

Subtract 15 from 82 to get 67.

$$\frac{67}{10}-\frac{2\times 10+7}{10}$$

Multiply 2 and 10 to get 20.

$$\frac{67}{10}-\frac{20+7}{10}$$

Add 20 and 7 to get 27.

$$\frac{67}{10}-\frac{27}{10}$$

Since \frac{67}{10} and \frac{27}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{67-27}{10}$$

Subtract 27 from 67 to get 40.

$$\frac{40}{10}$$

Divide 40 by 10 to get 4.

$$4$$

Factor

$$2^{2}$$