Solve 81/3-(2+25/8*4/5)

$$8 \frac { 1 } { 3 } - ( 2 + \frac { 25 } { 8 } \times \frac { 4 } { 5 } )$$

Evaluate

$$\frac{23}{6}\approx 3.833333333$$

Solution Steps

Multiply 8 and 3 to get 24.

$$\frac{24+1}{3}-\left(2+\frac{25}{8}\times \frac{4}{5}\right)$$

Add 24 and 1 to get 25.

$$\frac{25}{3}-\left(2+\frac{25}{8}\times \frac{4}{5}\right)$$

Multiply \frac{25}{8} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{25}{3}-\left(2+\frac{25\times 4}{8\times 5}\right)$$

Do the multiplications in the fraction \frac{25\times 4}{8\times 5}.

$$\frac{25}{3}-\left(2+\frac{100}{40}\right)$$

Reduce the fraction \frac{100}{40} to lowest terms by extracting and canceling out 20.

$$\frac{25}{3}-\left(2+\frac{5}{2}\right)$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{25}{3}-\left(\frac{4}{2}+\frac{5}{2}\right)$$

Since \frac{4}{2} and \frac{5}{2} have the same denominator, add them by adding their numerators.

$$\frac{25}{3}-\frac{4+5}{2}$$

Add 4 and 5 to get 9.

$$\frac{25}{3}-\frac{9}{2}$$

Least common multiple of 3 and 2 is 6. Convert \frac{25}{3} and \frac{9}{2} to fractions with denominator 6.

$$\frac{50}{6}-\frac{27}{6}$$

Since \frac{50}{6} and \frac{27}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{50-27}{6}$$

Subtract 27 from 50 to get 23.

$$\frac{23}{6}$$

Factor

$$\frac{23}{2 \cdot 3} = 3\frac{5}{6} = 3.8333333333333335$$