Solve 8^frac{1{3}}(1/2)^4:16^-1

$$8 ^ { \frac { 1 } { 3 } } ( \frac { 1 } { 2 } ) ^ { 4 } : 16 ^ { - 1 }$$

Evaluate

$$2$$

Solution Steps

Calculate 8 to the power of \frac{1}{3} and get 2.

$$\frac{2\times \left(\frac{1}{2}\right)^{4}}{16^{-1}}$$

Calculate \frac{1}{2} to the power of 4 and get \frac{1}{16}.

$$\frac{2\times \frac{1}{16}}{16^{-1}}$$

Multiply 2 and \frac{1}{16} to get \frac{1}{8}.

$$\frac{\frac{1}{8}}{16^{-1}}$$

Calculate 16 to the power of -1 and get \frac{1}{16}.

$$\frac{\frac{1}{8}}{\frac{1}{16}}$$

Divide \frac{1}{8} by \frac{1}{16} by multiplying \frac{1}{8} by the reciprocal of \frac{1}{16}.

$$\frac{1}{8}\times 16$$

Multiply \frac{1}{8} and 16 to get 2.

$$2$$

Factor

$$2$$