Solve for x
x=\frac{2\left(y-7z+252\right)}{7}
Solve for y
y=\frac{7\left(x+2z-72\right)}{2}
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7x+14z=504+2y
Add 2y to both sides.
7x=504+2y-14z
Subtract 14z from both sides.
7x=2y-14z+504
The equation is in standard form.
\frac{7x}{7}=\frac{2y-14z+504}{7}
Divide both sides by 7.
x=\frac{2y-14z+504}{7}
Dividing by 7 undoes the multiplication by 7.
x=\frac{2y}{7}-2z+72
Divide 504+2y-14z by 7.
-2y+14z=504-7x
Subtract 7x from both sides.
-2y=504-7x-14z
Subtract 14z from both sides.
-2y=504-14z-7x
The equation is in standard form.
\frac{-2y}{-2}=\frac{504-14z-7x}{-2}
Divide both sides by -2.
y=\frac{504-14z-7x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{7x}{2}+7z-252
Divide 504-7x-14z by -2.
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