Solve 7x-20-2=0+-41x-122

$$7x-20-2=0+-41x-122$$

Solve for x

$$x = -\frac{25}{12} = -2\frac{1}{12} \approx -2.083333333$$

Steps for Solving Linear Equation

Subtract 2 from -20 to get -22.

$$7x-22=0-41x-122$$

Subtract 122 from 0 to get -122.

$$7x-22=-122-41x$$

Add 41x to both sides.

$$7x-22+41x=-122$$

Combine 7x and 41x to get 48x.

$$48x-22=-122$$

Add 22 to both sides.

$$48x=-122+22$$

Add -122 and 22 to get -100.

$$48x=-100$$

Divide both sides by 48.

$$x=\frac{-100}{48}$$

Reduce the fraction \frac{-100}{48} to lowest terms by extracting and canceling out 4.

$$x=-\frac{25}{12}$$