Solve for x
x=\frac{65+8z-4y}{7}
Solve for y
y=-\frac{7x}{4}+2z+\frac{65}{4}
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7x-8z=65-4y
Subtract 4y from both sides.
7x=65-4y+8z
Add 8z to both sides.
7x=65+8z-4y
The equation is in standard form.
\frac{7x}{7}=\frac{65+8z-4y}{7}
Divide both sides by 7.
x=\frac{65+8z-4y}{7}
Dividing by 7 undoes the multiplication by 7.
4y-8z=65-7x
Subtract 7x from both sides.
4y=65-7x+8z
Add 8z to both sides.
4y=65+8z-7x
The equation is in standard form.
\frac{4y}{4}=\frac{65+8z-7x}{4}
Divide both sides by 4.
y=\frac{65+8z-7x}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{7x}{4}+2z+\frac{65}{4}
Divide 65-7x+8z by 4.
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