Solve for x
x = \frac{2 \sqrt{3} + 9}{7} \approx 1.780585945
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7x=9+3\sqrt{3}-\sqrt{3}
Subtract \sqrt{3} from both sides.
7x=9+2\sqrt{3}
Combine 3\sqrt{3} and -\sqrt{3} to get 2\sqrt{3}.
7x=2\sqrt{3}+9
The equation is in standard form.
\frac{7x}{7}=\frac{2\sqrt{3}+9}{7}
Divide both sides by 7.
x=\frac{2\sqrt{3}+9}{7}
Dividing by 7 undoes the multiplication by 7.
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