Solve for x (complex solution)
x=\frac{-5\sqrt{61}i+55}{2}\approx 27.5-19.52562419i
x=\frac{55+5\sqrt{61}i}{2}\approx 27.5+19.52562419i
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750=x^{2}+\left(55-x\right)^{2}
Divide each term of 110-2x by 2 to get 55-x.
750=x^{2}+3025-110x+x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(55-x\right)^{2}.
750=2x^{2}+3025-110x
Combine x^{2} and x^{2} to get 2x^{2}.
2x^{2}+3025-110x=750
Swap sides so that all variable terms are on the left hand side.
2x^{2}+3025-110x-750=0
Subtract 750 from both sides.
2x^{2}+2275-110x=0
Subtract 750 from 3025 to get 2275.
2x^{2}-110x+2275=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-110\right)±\sqrt{\left(-110\right)^{2}-4\times 2\times 2275}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, -110 for b, and 2275 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-110\right)±\sqrt{12100-4\times 2\times 2275}}{2\times 2}
Square -110.
x=\frac{-\left(-110\right)±\sqrt{12100-8\times 2275}}{2\times 2}
Multiply -4 times 2.
x=\frac{-\left(-110\right)±\sqrt{12100-18200}}{2\times 2}
Multiply -8 times 2275.
x=\frac{-\left(-110\right)±\sqrt{-6100}}{2\times 2}
Add 12100 to -18200.
x=\frac{-\left(-110\right)±10\sqrt{61}i}{2\times 2}
Take the square root of -6100.
x=\frac{110±10\sqrt{61}i}{2\times 2}
The opposite of -110 is 110.
x=\frac{110±10\sqrt{61}i}{4}
Multiply 2 times 2.
x=\frac{110+10\sqrt{61}i}{4}
Now solve the equation x=\frac{110±10\sqrt{61}i}{4} when ± is plus. Add 110 to 10i\sqrt{61}.
x=\frac{55+5\sqrt{61}i}{2}
Divide 110+10i\sqrt{61} by 4.
x=\frac{-10\sqrt{61}i+110}{4}
Now solve the equation x=\frac{110±10\sqrt{61}i}{4} when ± is minus. Subtract 10i\sqrt{61} from 110.
x=\frac{-5\sqrt{61}i+55}{2}
Divide 110-10i\sqrt{61} by 4.
x=\frac{55+5\sqrt{61}i}{2} x=\frac{-5\sqrt{61}i+55}{2}
The equation is now solved.
750=x^{2}+\left(55-x\right)^{2}
Divide each term of 110-2x by 2 to get 55-x.
750=x^{2}+3025-110x+x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(55-x\right)^{2}.
750=2x^{2}+3025-110x
Combine x^{2} and x^{2} to get 2x^{2}.
2x^{2}+3025-110x=750
Swap sides so that all variable terms are on the left hand side.
2x^{2}-110x=750-3025
Subtract 3025 from both sides.
2x^{2}-110x=-2275
Subtract 3025 from 750 to get -2275.
\frac{2x^{2}-110x}{2}=-\frac{2275}{2}
Divide both sides by 2.
x^{2}+\left(-\frac{110}{2}\right)x=-\frac{2275}{2}
Dividing by 2 undoes the multiplication by 2.
x^{2}-55x=-\frac{2275}{2}
Divide -110 by 2.
x^{2}-55x+\left(-\frac{55}{2}\right)^{2}=-\frac{2275}{2}+\left(-\frac{55}{2}\right)^{2}
Divide -55, the coefficient of the x term, by 2 to get -\frac{55}{2}. Then add the square of -\frac{55}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-55x+\frac{3025}{4}=-\frac{2275}{2}+\frac{3025}{4}
Square -\frac{55}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-55x+\frac{3025}{4}=-\frac{1525}{4}
Add -\frac{2275}{2} to \frac{3025}{4} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-\frac{55}{2}\right)^{2}=-\frac{1525}{4}
Factor x^{2}-55x+\frac{3025}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{55}{2}\right)^{2}}=\sqrt{-\frac{1525}{4}}
Take the square root of both sides of the equation.
x-\frac{55}{2}=\frac{5\sqrt{61}i}{2} x-\frac{55}{2}=-\frac{5\sqrt{61}i}{2}
Simplify.
x=\frac{55+5\sqrt{61}i}{2} x=\frac{-5\sqrt{61}i+55}{2}
Add \frac{55}{2} to both sides of the equation.
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