Solve 75+0.3xleq35+0.8x

$$75+0.3x \leq 35+0.8x$$

Solve for x

$$x\geq 80$$

Solution Steps

Subtract 0.8x from both sides.

$$75+0.3x-0.8x\leq 35$$

Combine 0.3x and -0.8x to get -0.5x.

$$75-0.5x\leq 35$$

Subtract 75 from both sides.

$$-0.5x\leq 35-75$$

Subtract 75 from 35 to get -40.

$$-0.5x\leq -40$$

Divide both sides by -0.5. Since -0.5 is negative, the inequality direction is changed.

$$x\geq \frac{-40}{-0.5}$$

Expand \frac{-40}{-0.5} by multiplying both numerator and the denominator by 10.

$$x\geq \frac{-400}{-5}$$

Divide -400 by -5 to get 80.

$$x\geq 80$$