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75e^{0.1t}=10
Use the rules of exponents and logarithms to solve the equation.
e^{0.1t}=\frac{2}{15}
Divide both sides by 75.
\log(e^{0.1t})=\log(\frac{2}{15})
Take the logarithm of both sides of the equation.
0.1t\log(e)=\log(\frac{2}{15})
The logarithm of a number raised to a power is the power times the logarithm of the number.
0.1t=\frac{\log(\frac{2}{15})}{\log(e)}
Divide both sides by \log(e).
0.1t=\log_{e}\left(\frac{2}{15}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
t=\frac{\ln(\frac{2}{15})}{0.1}
Multiply both sides by 10.