Solve 740+22(N-12)=650+30(11-10)

$$740 + 22 ( N - 12 ) = 650 + 30 ( 11 - 10 )$$

Solve for N

$$N = \frac{102}{11} = 9\frac{3}{11} \approx 9.272727273$$

Steps for Solving Linear Equation

Use the distributive property to multiply 22 by N-12.

$$740+22N-264=650+30\left(11-10\right)$$

Subtract 264 from 740 to get 476.

$$476+22N=650+30\left(11-10\right)$$

Subtract 10 from 11 to get 1.

$$476+22N=650+30\times 1$$

Multiply 30 and 1 to get 30.

$$476+22N=650+30$$

Add 650 and 30 to get 680.

$$476+22N=680$$

Subtract 476 from both sides.

$$22N=680-476$$

Subtract 476 from 680 to get 204.

$$22N=204$$

Divide both sides by 22.

$$N=\frac{204}{22}$$

Reduce the fraction \frac{204}{22} to lowest terms by extracting and canceling out 2.

$$N=\frac{102}{11}$$