Solve 72sqrt{2}div4sqrt{3}div3sqrt{2}=

$$72 \sqrt { 2 } \div 4 \sqrt { 3 } \div 3 \sqrt { 2 } =$$

Evaluate

$$12\sqrt{3}\approx 20.784609691$$

Solution Steps

Divide 72\sqrt{2} by 4 to get 18\sqrt{2}.

$$\frac{18\sqrt{2}\sqrt{3}}{3}\sqrt{2}$$

To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.

$$\frac{18\sqrt{6}}{3}\sqrt{2}$$

Divide 18\sqrt{6} by 3 to get 6\sqrt{6}.

$$6\sqrt{6}\sqrt{2}$$

Factor 6=2\times 3. Rewrite the square root of the product \sqrt{2\times 3} as the product of square roots \sqrt{2}\sqrt{3}.

$$6\sqrt{2}\sqrt{3}\sqrt{2}$$

Multiply \sqrt{2} and \sqrt{2} to get 2.

$$6\times 2\sqrt{3}$$

Multiply 6 and 2 to get 12.

$$12\sqrt{3}$$