Solve for B
B=-\frac{6}{C}
C\neq 0
Solve for C
C=-\frac{6}{B}
B\neq 0
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6BC+108=72
Swap sides so that all variable terms are on the left hand side.
6BC=72-108
Subtract 108 from both sides.
6BC=-36
Subtract 108 from 72 to get -36.
6CB=-36
The equation is in standard form.
\frac{6CB}{6C}=-\frac{36}{6C}
Divide both sides by 6C.
B=-\frac{36}{6C}
Dividing by 6C undoes the multiplication by 6C.
B=-\frac{6}{C}
Divide -36 by 6C.
6BC+108=72
Swap sides so that all variable terms are on the left hand side.
6BC=72-108
Subtract 108 from both sides.
6BC=-36
Subtract 108 from 72 to get -36.
\frac{6BC}{6B}=-\frac{36}{6B}
Divide both sides by 6B.
C=-\frac{36}{6B}
Dividing by 6B undoes the multiplication by 6B.
C=-\frac{6}{B}
Divide -36 by 6B.
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