Solve 71-(53-(-7)]+(3*(18-15)+5*[2*(-7+5)])=

$$71 - ( 53 - ( - 7 ) ] + ( 3 \cdot ( 18 - 15 ) + 5 \cdot [ 2 \cdot ( - 7 + 5 ) ] ) =$$

Evaluate

$$0$$

Solution Steps

The opposite of -7 is 7.

$$71-\left(53+7\right)+3\left(18-15\right)+5\times 2\left(-7+5\right)$$

Add 53 and 7 to get 60.

$$71-60+3\left(18-15\right)+5\times 2\left(-7+5\right)$$

Subtract 60 from 71 to get 11.

$$11+3\left(18-15\right)+5\times 2\left(-7+5\right)$$

Subtract 15 from 18 to get 3.

$$11+3\times 3+5\times 2\left(-7+5\right)$$

Multiply 3 and 3 to get 9.

$$11+9+5\times 2\left(-7+5\right)$$

Add 11 and 9 to get 20.

$$20+5\times 2\left(-7+5\right)$$

Multiply 5 and 2 to get 10.

$$20+10\left(-7+5\right)$$

Add -7 and 5 to get -2.

$$20+10\left(-2\right)$$

Multiply 10 and -2 to get -20.

$$20-20$$

Subtract 20 from 20 to get 0.

$$0$$

Factor

$$0$$