Solve 70.5+(270/4-39/33)*10

$$70.5+( \frac{ \frac{ 270 }{ 4 } -39 }{ 33 } ) \times 10$$

Evaluate

$$\frac{1741}{22}\approx 79.136363636$$

Solution Steps

Reduce the fraction \frac{270}{4} to lowest terms by extracting and canceling out 2.

$$70.5+\frac{\frac{135}{2}-39}{33}\times 10$$

Convert 39 to fraction \frac{78}{2}.

$$70.5+\frac{\frac{135}{2}-\frac{78}{2}}{33}\times 10$$

Since \frac{135}{2} and \frac{78}{2} have the same denominator, subtract them by subtracting their numerators.

$$70.5+\frac{\frac{135-78}{2}}{33}\times 10$$

Subtract 78 from 135 to get 57.

$$70.5+\frac{\frac{57}{2}}{33}\times 10$$

Express \frac{\frac{57}{2}}{33} as a single fraction.

$$70.5+\frac{57}{2\times 33}\times 10$$

Multiply 2 and 33 to get 66.

$$70.5+\frac{57}{66}\times 10$$

Reduce the fraction \frac{57}{66} to lowest terms by extracting and canceling out 3.

$$70.5+\frac{19}{22}\times 10$$

Express \frac{19}{22}\times 10 as a single fraction.

$$70.5+\frac{19\times 10}{22}$$

Multiply 19 and 10 to get 190.

$$70.5+\frac{190}{22}$$

Reduce the fraction \frac{190}{22} to lowest terms by extracting and canceling out 2.

$$70.5+\frac{95}{11}$$

Convert decimal number 70.5 to fraction \frac{705}{10}. Reduce the fraction \frac{705}{10} to lowest terms by extracting and canceling out 5.

$$\frac{141}{2}+\frac{95}{11}$$

Least common multiple of 2 and 11 is 22. Convert \frac{141}{2} and \frac{95}{11} to fractions with denominator 22.

$$\frac{1551}{22}+\frac{190}{22}$$

Since \frac{1551}{22} and \frac{190}{22} have the same denominator, add them by adding their numerators.

$$\frac{1551+190}{22}$$

Add 1551 and 190 to get 1741.

$$\frac{1741}{22}$$

Factor

$$\frac{1741}{2 \cdot 11} = 79\frac{3}{22} = 79.13636363636364$$