Solve 7(x+3)+5(x4)=2

$$7(x+3)+5(x4)=2$$

Solve for x

$$x=\frac{-5x_{4}-19}{7}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 7 by x+3.

$$7x+21+5x_{4}=2$$

Subtract 21 from both sides.

$$7x+5x_{4}=2-21$$

Subtract 21 from 2 to get -19.

$$7x+5x_{4}=-19$$

Subtract 5x_{4} from both sides.

$$7x=-19-5x_{4}$$

The equation is in standard form.

$$7x=-5x_{4}-19$$

Divide both sides by 7.

$$\frac{7x}{7}=\frac{-5x_{4}-19}{7}$$

Dividing by 7 undoes the multiplication by 7.

$$x=\frac{-5x_{4}-19}{7}$$

Solve for x_4

$$x_{4}=\frac{-7x-19}{5}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 7 by x+3.

$$7x+21+5x_{4}=2$$

Subtract 7x from both sides.

$$21+5x_{4}=2-7x$$

Subtract 21 from both sides.

$$5x_{4}=2-7x-21$$

Subtract 21 from 2 to get -19.

$$5x_{4}=-19-7x$$

The equation is in standard form.

$$5x_{4}=-7x-19$$

Divide both sides by 5.

$$\frac{5x_{4}}{5}=\frac{-7x-19}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x_{4}=\frac{-7x-19}{5}$$