Solve for x
x=\frac{5y}{7}+1
Solve for y
y=\frac{7\left(x-1\right)}{5}
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7x=7+5y
Add 5y to both sides.
7x=5y+7
The equation is in standard form.
\frac{7x}{7}=\frac{5y+7}{7}
Divide both sides by 7.
x=\frac{5y+7}{7}
Dividing by 7 undoes the multiplication by 7.
x=\frac{5y}{7}+1
Divide 7+5y by 7.
-5y=7-7x
Subtract 7x from both sides.
\frac{-5y}{-5}=\frac{7-7x}{-5}
Divide both sides by -5.
y=\frac{7-7x}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{7x-7}{5}
Divide 7-7x by -5.
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