Solve for x
x=\frac{2\left(y+3\right)}{7}
Solve for y
y=\frac{7x}{2}-3
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7x=6+2y
Add 2y to both sides.
7x=2y+6
The equation is in standard form.
\frac{7x}{7}=\frac{2y+6}{7}
Divide both sides by 7.
x=\frac{2y+6}{7}
Dividing by 7 undoes the multiplication by 7.
-2y=6-7x
Subtract 7x from both sides.
\frac{-2y}{-2}=\frac{6-7x}{-2}
Divide both sides by -2.
y=\frac{6-7x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{7x}{2}-3
Divide 6-7x by -2.
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