Solve 7x-[14-(2x+5)]=18-[3x+(15-4x)]

$$7 x - [ 14 - ( 2 x + 5 ) ] = 18 - [ 3 x + ( 15 - 4 x ) ]$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

To find the opposite of 2x+5, find the opposite of each term.

$$7x-\left(14-2x-5\right)=18-\left(3x+15-4x\right)$$

Subtract 5 from 14 to get 9.

$$7x-\left(9-2x\right)=18-\left(3x+15-4x\right)$$

To find the opposite of 9-2x, find the opposite of each term.

$$7x-9-\left(-2x\right)=18-\left(3x+15-4x\right)$$

The opposite of -2x is 2x.

$$7x-9+2x=18-\left(3x+15-4x\right)$$

Combine 7x and 2x to get 9x.

$$9x-9=18-\left(3x+15-4x\right)$$

Combine 3x and -4x to get -x.

$$9x-9=18-\left(-x+15\right)$$

To find the opposite of -x+15, find the opposite of each term.

$$9x-9=18-\left(-x\right)-15$$

The opposite of -x is x.

$$9x-9=18+x-15$$

Subtract 15 from 18 to get 3.

$$9x-9=3+x$$

Subtract x from both sides.

$$9x-9-x=3$$

Combine 9x and -x to get 8x.

$$8x-9=3$$

Add 9 to both sides.

$$8x=3+9$$

Add 3 and 9 to get 12.

$$8x=12$$

Divide both sides by 8.

$$x=\frac{12}{8}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$x=\frac{3}{2}$$