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7x^{2}+9x=0
Add 9x to both sides.
x\left(7x+9\right)=0
Factor out x.
x=0 x=-\frac{9}{7}
To find equation solutions, solve x=0 and 7x+9=0.
7x^{2}+9x=0
Add 9x to both sides.
x=\frac{-9±\sqrt{9^{2}}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, 9 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-9±9}{2\times 7}
Take the square root of 9^{2}.
x=\frac{-9±9}{14}
Multiply 2 times 7.
x=\frac{0}{14}
Now solve the equation x=\frac{-9±9}{14} when ± is plus. Add -9 to 9.
x=0
Divide 0 by 14.
x=-\frac{18}{14}
Now solve the equation x=\frac{-9±9}{14} when ± is minus. Subtract 9 from -9.
x=-\frac{9}{7}
Reduce the fraction \frac{-18}{14} to lowest terms by extracting and canceling out 2.
x=0 x=-\frac{9}{7}
The equation is now solved.
7x^{2}+9x=0
Add 9x to both sides.
\frac{7x^{2}+9x}{7}=\frac{0}{7}
Divide both sides by 7.
x^{2}+\frac{9}{7}x=\frac{0}{7}
Dividing by 7 undoes the multiplication by 7.
x^{2}+\frac{9}{7}x=0
Divide 0 by 7.
x^{2}+\frac{9}{7}x+\left(\frac{9}{14}\right)^{2}=\left(\frac{9}{14}\right)^{2}
Divide \frac{9}{7}, the coefficient of the x term, by 2 to get \frac{9}{14}. Then add the square of \frac{9}{14} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{9}{7}x+\frac{81}{196}=\frac{81}{196}
Square \frac{9}{14} by squaring both the numerator and the denominator of the fraction.
\left(x+\frac{9}{14}\right)^{2}=\frac{81}{196}
Factor x^{2}+\frac{9}{7}x+\frac{81}{196}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{9}{14}\right)^{2}}=\sqrt{\frac{81}{196}}
Take the square root of both sides of the equation.
x+\frac{9}{14}=\frac{9}{14} x+\frac{9}{14}=-\frac{9}{14}
Simplify.
x=0 x=-\frac{9}{7}
Subtract \frac{9}{14} from both sides of the equation.