Solve 7x^2+6div2=8

$$7 x ^ { 2 } + 6 \div 2 = 8$$

Solve for x

$$x=\frac{\sqrt{35}}{7}\approx 0.845154255$$

$$x=-\frac{\sqrt{35}}{7}\approx -0.845154255$$

Steps by Finding Square Root

Divide 6 by 2 to get 3.

$$7x^{2}+3=8$$

Subtract 3 from both sides.

$$7x^{2}=8-3$$

Subtract 3 from 8 to get 5.

$$7x^{2}=5$$

Divide both sides by 7.

$$x^{2}=\frac{5}{7}$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{35}}{7} x=-\frac{\sqrt{35}}{7}$$

Steps Using the Quadratic Formula

Divide 6 by 2 to get 3.

$$7x^{2}+3=8$$

Subtract 8 from both sides.

$$7x^{2}+3-8=0$$

Subtract 8 from 3 to get -5.

$$7x^{2}-5=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, 0 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 7\left(-5\right)}}{2\times 7}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 7\left(-5\right)}}{2\times 7}$$

Multiply -4 times 7.

$$x=\frac{0±\sqrt{-28\left(-5\right)}}{2\times 7}$$

Multiply -28 times -5.

$$x=\frac{0±\sqrt{140}}{2\times 7}$$

Take the square root of 140.

$$x=\frac{0±2\sqrt{35}}{2\times 7}$$

Multiply 2 times 7.

$$x=\frac{0±2\sqrt{35}}{14}$$

Now solve the equation x=\frac{0±2\sqrt{35}}{14} when ± is plus.

$$x=\frac{\sqrt{35}}{7}$$

Now solve the equation x=\frac{0±2\sqrt{35}}{14} when ± is minus.

$$x=-\frac{\sqrt{35}}{7}$$

The equation is now solved.

$$x=\frac{\sqrt{35}}{7} x=-\frac{\sqrt{35}}{7}$$