Solve 7x^2+36x+5

$$7 x ^ { 2 } + 36 x + 5$$

Factor

$$\left(x+5\right)\left(7x+1\right)$$

Solution Steps

Factor the expression by grouping. First, the expression needs to be rewritten as 7x^{2}+ax+bx+5. To find a and b, set up a system to be solved.

$$a+b=36 ab=7\times 5=35$$

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 35.

$$1,35 5,7$$

Calculate the sum for each pair.

$$1+35=36 5+7=12$$

The solution is the pair that gives sum 36.

$$a=1 b=35$$

Rewrite 7x^{2}+36x+5 as \left(7x^{2}+x\right)+\left(35x+5\right).

$$\left(7x^{2}+x\right)+\left(35x+5\right)$$

Factor out x in the first and 5 in the second group.

$$x\left(7x+1\right)+5\left(7x+1\right)$$

Factor out common term 7x+1 by using distributive property.

$$\left(7x+1\right)\left(x+5\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$7x^{2}+36x+5=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-36±\sqrt{36^{2}-4\times 7\times 5}}{2\times 7}$$

Square 36.

$$x=\frac{-36±\sqrt{1296-4\times 7\times 5}}{2\times 7}$$

Multiply -4 times 7.

$$x=\frac{-36±\sqrt{1296-28\times 5}}{2\times 7}$$

Multiply -28 times 5.

$$x=\frac{-36±\sqrt{1296-140}}{2\times 7}$$

Add 1296 to -140.

$$x=\frac{-36±\sqrt{1156}}{2\times 7}$$

Take the square root of 1156.

$$x=\frac{-36±34}{2\times 7}$$

Multiply 2 times 7.

$$x=\frac{-36±34}{14}$$

Now solve the equation x=\frac{-36±34}{14} when ± is plus. Add -36 to 34.

$$x=-\frac{2}{14}$$

Reduce the fraction \frac{-2}{14} to lowest terms by extracting and canceling out 2.

$$x=-\frac{1}{7}$$

Now solve the equation x=\frac{-36±34}{14} when ± is minus. Subtract 34 from -36.

$$x=-\frac{70}{14}$$

Divide -70 by 14.

$$x=-5$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -\frac{1}{7} for x_{1} and -5 for x_{2}.

$$7x^{2}+36x+5=7\left(x-\left(-\frac{1}{7}\right)\right)\left(x-\left(-5\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$7x^{2}+36x+5=7\left(x+\frac{1}{7}\right)\left(x+5\right)$$

Add \frac{1}{7} to x by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

$$7x^{2}+36x+5=7\times \frac{7x+1}{7}\left(x+5\right)$$

Cancel out 7, the greatest common factor in 7 and 7.

$$7x^{2}+36x+5=\left(7x+1\right)\left(x+5\right)$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 7

$$x ^ 2 +\frac{36}{7}x +\frac{5}{7} = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = -\frac{36}{7} rs = \frac{5}{7}$$

Two numbers r and s sum up to -\frac{36}{7} exactly when the average of the two numbers is \frac{1}{2}*-\frac{36}{7} = -\frac{18}{7}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = -\frac{18}{7} - u s = -\frac{18}{7} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = \frac{5}{7}

$$(-\frac{18}{7} - u) (-\frac{18}{7} + u) = \frac{5}{7}$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{324}{49} - u^2 = \frac{5}{7}$$

Simplify the expression by subtracting \frac{324}{49} on both sides

$$-u^2 = \frac{5}{7}-\frac{324}{49} = -\frac{289}{49}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{289}{49} u = \pm\sqrt{\frac{289}{49}} = \pm \frac{17}{7}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =-\frac{18}{7} - \frac{17}{7} = -5 s = -\frac{18}{7} + \frac{17}{7} = -0.143$$

Evaluate

$$\left(x+5\right)\left(7x+1\right)$$