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7xx=11+x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
7x^{2}=11+x
Multiply x and x to get x^{2}.
7x^{2}-11=x
Subtract 11 from both sides.
7x^{2}-11-x=0
Subtract x from both sides.
7x^{2}-x-11=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-1\right)±\sqrt{1-4\times 7\left(-11\right)}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, -1 for b, and -11 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-1\right)±\sqrt{1-28\left(-11\right)}}{2\times 7}
Multiply -4 times 7.
x=\frac{-\left(-1\right)±\sqrt{1+308}}{2\times 7}
Multiply -28 times -11.
x=\frac{-\left(-1\right)±\sqrt{309}}{2\times 7}
Add 1 to 308.
x=\frac{1±\sqrt{309}}{2\times 7}
The opposite of -1 is 1.
x=\frac{1±\sqrt{309}}{14}
Multiply 2 times 7.
x=\frac{\sqrt{309}+1}{14}
Now solve the equation x=\frac{1±\sqrt{309}}{14} when ± is plus. Add 1 to \sqrt{309}.
x=\frac{1-\sqrt{309}}{14}
Now solve the equation x=\frac{1±\sqrt{309}}{14} when ± is minus. Subtract \sqrt{309} from 1.
x=\frac{\sqrt{309}+1}{14} x=\frac{1-\sqrt{309}}{14}
The equation is now solved.
7xx=11+x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
7x^{2}=11+x
Multiply x and x to get x^{2}.
7x^{2}-x=11
Subtract x from both sides.
\frac{7x^{2}-x}{7}=\frac{11}{7}
Divide both sides by 7.
x^{2}-\frac{1}{7}x=\frac{11}{7}
Dividing by 7 undoes the multiplication by 7.
x^{2}-\frac{1}{7}x+\left(-\frac{1}{14}\right)^{2}=\frac{11}{7}+\left(-\frac{1}{14}\right)^{2}
Divide -\frac{1}{7}, the coefficient of the x term, by 2 to get -\frac{1}{14}. Then add the square of -\frac{1}{14} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-\frac{1}{7}x+\frac{1}{196}=\frac{11}{7}+\frac{1}{196}
Square -\frac{1}{14} by squaring both the numerator and the denominator of the fraction.
x^{2}-\frac{1}{7}x+\frac{1}{196}=\frac{309}{196}
Add \frac{11}{7} to \frac{1}{196} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-\frac{1}{14}\right)^{2}=\frac{309}{196}
Factor x^{2}-\frac{1}{7}x+\frac{1}{196}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{1}{14}\right)^{2}}=\sqrt{\frac{309}{196}}
Take the square root of both sides of the equation.
x-\frac{1}{14}=\frac{\sqrt{309}}{14} x-\frac{1}{14}=-\frac{\sqrt{309}}{14}
Simplify.
x=\frac{\sqrt{309}+1}{14} x=\frac{1-\sqrt{309}}{14}
Add \frac{1}{14} to both sides of the equation.