Solve for x
x=\frac{48-3y}{7}
Solve for y
y=-\frac{7x}{3}+16
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7x=48-3y
Subtract 3y from both sides.
\frac{7x}{7}=\frac{48-3y}{7}
Divide both sides by 7.
x=\frac{48-3y}{7}
Dividing by 7 undoes the multiplication by 7.
3y=48-7x
Subtract 7x from both sides.
\frac{3y}{3}=\frac{48-7x}{3}
Divide both sides by 3.
y=\frac{48-7x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{7x}{3}+16
Divide 48-7x by 3.
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