Solve for x
x=\frac{-2y-8}{7}
Solve for y
y=-\frac{7x}{2}-4
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7x+8=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
7x=-2y-8
Subtract 8 from both sides.
\frac{7x}{7}=\frac{-2y-8}{7}
Divide both sides by 7.
x=\frac{-2y-8}{7}
Dividing by 7 undoes the multiplication by 7.
2y+8=-7x
Subtract 7x from both sides. Anything subtracted from zero gives its negation.
2y=-7x-8
Subtract 8 from both sides.
\frac{2y}{2}=\frac{-7x-8}{2}
Divide both sides by 2.
y=\frac{-7x-8}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{7x}{2}-4
Divide -7x-8 by 2.
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